This answered two of my posts which led to other post with also solved answer
For anyone who came here in future:
Here is what I did. I was using array in this post because dict didn't work another day (in that same link) so I tested array and it results the same thing as dict. I made a mistake by using parse on array when it should be dict. I did not realize my dict output is not json configured properly. Here is the tool that helps you to confirm if it's parsable or not. So I reverted my code back to other post to solve this issue.
If you are here for array only, here is what I did with an array only then I went back to dict after this post answered:
here is what I did to turn the output into 1D.
if stored_value != "":
var array_test = stored_value.replace("[", "")
array_test = array_test.replace("]", "")
test=array_test.split(",", true, '0')
Basically, stored_value gets output like this:
[[5, 6, 1], [8, 3, 7], [4, 4, 3], [1, 1, 6], [9, 9, 7], [2, 9, 3], [3, 2, 7], [4, 5, 1], [9, 3, 2], [8, 5, 6], [4, 4, 5], [4, 6, 2], [2, 4, 9], [9, 2, 3], [1, 4, 4], [7, 6, 1], [1, 9, 3], [9, 7, 2], [3, 8, 6], [4, 8, 2], [7, 9, 9], [4, 6, 4], [1, 4, 6], [2, 9, 7], [3, 6, 2], [1, 9, 5], [3, 4, 4], [7, 2, 5], [8, 9, 1], [3, 8, 1], [7, 6, 5], [8, 2, 5], [8, 7, 1], [5, 5, 4], [6, 9, 8], [9, 9, 6], [6, 6, 5], [6, 3, 6], [9, 9, 8], [5, 1, 2], [7, 6, 6], [8, 8, 7], [3, 3, 9], [6, 1, 8], [4, 5, 2], [6, 9, 3], [1, 5, 7], [9, 3, 6], [1, 7, 4], [5, 5, 8], [3, 7, 6], [2, 4, 1], [8, 2, 2], [5, 7, 8], [9, 7, 3], [1, 9, 4], [8, 6, 2], [5, 4, 3], [2, 1, 7], [2, 2, 6], [4, 1, 9], [2, 6, 6], [5, 8, 5], [4, 4, 4], [9, 5, 1], [6, 7, 3], [5, 5, 5], [9, 3, 3], [4, 2, 3], [4, 6, 3], [7, 2, 2], [1, 1, 9], [9, 5, 3], [8, 9, 7], [1, 8, 5], [6, 9, 2], [7, 4, 2], [5, 4, 9], [7, 2, 4], [1, 4, 7], [2, 8, 9], [8, 9, 9], [2, 3, 7], [8, 7, 9], [6, 3, 3], [3, 1, 6], [3, 3, 3], [9, 5, 7], [6, 1, 5], [3, 8, 2], [1, 8, 9], [9, 6, 8]]
to this processed output:
[5, 6, 1, 8, 3, 7, 4, 4, 3, 1, 1, 6, 9, 9, 7, 2, 9, 3, 3, 2, 7, 4, 5, 1, 9, 3, 2, 8, 5, 6, 4, 4, 5, 4, 6, 2, 2, 4, 9, 9, 2, 3, 1, 4, 4, 7, 6, 1, 1, 9, 3, 9, 7, 2, 3, 8, 6, 4, 8, 2, 7, 9, 9, 4, 6, 4, 1, 4, 6, 2, 9, 7, 3, 6, 2, 1, 9, 5, 3, 4, 4, 7, 2, 5, 8, 9, 1, 3, 8, 1, 7, 6, 5, 8, 2, 5, 8, 7, 1, 5, 5, 4, 6, 9, 8, 9, 9, 6, 6, 6, 5, 6, 3, 6, 9, 9, 8, 5, 1, 2, 7, 6, 6, 8, 8, 7, 3, 3, 9, 6, 1, 8, 4, 5, 2, 6, 9, 3, 1, 5, 7, 9, 3, 6, 1, 7, 4, 5, 5, 8, 3, 7, 6, 2, 4, 1, 8, 2, 2, 5, 7, 8, 9, 7, 3, 1, 9, 4, 8, 6, 2, 5, 4, 3, 2, 1, 7, 2, 2, 6, 4, 1, 9, 2, 6, 6, 5, 8, 5, 4, 4, 4, 9, 5, 1, 6, 7, 3, 5, 5, 5, 9, 3, 3, 4, 2, 3, 4, 6, 3, 7, 2, 2, 1, 1, 9, 9, 5, 3, 8, 9, 7, 1, 8, 5, 6, 9, 2, 7, 4, 2, 5, 4, 9, 7, 2, 4, 1, 4, 7, 2, 8, 9, 8, 9, 9, 2, 3, 7, 8, 7, 9, 6, 3, 3, 3, 1, 6, 3, 3, 3, 9, 5, 7, 6, 1, 5, 3, 8, 2, 1, 8, 9, 9, 6, 8]
So, I did something like this to generate x,y,z:
while key < total:
if flag == 0:
flag = flag + 1
x = int(test[key])
elif flag == 1:
flag = flag + 1
y = int(test[key])
elif flag == 2:
flag = 0
z = int(test[key])
$GridMap.set_cell_item(x,y,z, 0)
Obv, you will have your own goal. This is only example for you to get the idea. Hopefully, you have a better idea than this.
By the time you come to here, I'm probably more experience by that time (approx 3 months from now on) so feel free to ask or correct me (if you caught something off so you can educate others and me)
Spacejase, thank you for your time!!!