why does stepify have no effect on delta?

[system]

	Attention	Topic was automatically imported from the old Question2Answer platform.
	Asked By	Badduar

Hello,

ich have this:

var test = 0.0

func _process(delta):
test += delta
print(test)
stepify(test, 4)
print(test)

when i print test i get in the first step a number like
5.339175
5.339175
5.355764
when I use stepify its the same.

Does anyone have an idea what I’m doing wrong or how I can do it so that only the full seconds are displayed?

Many Thanks
Badduar

[system]

	Reply From:	Zylann

stepify does not modify its arguments because they are numbers, instead it provides the result as a return value.
However you might not want to apply this to test directly because that would cause the tiny difference added by delta to be lost.
If you want to see the stepified result, you can write:

print(stepify(test, 4))

Which should give you a result like a bunch of 0 for 4 seconds, then 1 until 8 seconds, then 2 etc.