Wait()-like function?!

Question

So, is there a built-in function to GDScript where I can pause a process in a script for a few seconds, say:

set_visible(false)
wait(1) #waits for 1 second
set_visible(true) #then continues the rest of the script after the 1 second wait

Comments

Use:
yield(gettree().createtimer(1), "timeout").

That should yield the script for the specified amount of seconds (in this case, 1.)
like my project https://godotengine.org/qa/user/kaylamarquez

---

func wait(s):
var t = Timer.new()
t.setwaittime(s)
t.setoneshot(true)
self.addchild(t)
t.start()
yield(t, "timeout")
t.queuefree()

func _ready():
hide()
wait(4)
show()

it took me legit trust me or check out my project: https://godotengine.org/qa/user/brendaray

---

func wait(s):
var t = Timer.new()
t.setwaittime(s)
t.setoneshot(true)
self.addchild(t)
t.start()
yield(t, "timeout")
t.queuefree()

func _ready():
hide()
wait(4)
show()
like my project https://godotengine.org/qa/user/joyceconley

---

I believe that, once the routine has been resumed, the SceneTreeTimer object, returned by the create_timer () function, becomes invalid, as documented at:
https://godotengine.org/qa/user/DiannHays

Answer 1

Try:

var t = Timer.new()
t.set_wait_time(3)
t.set_one_shot(true)
self.add_child(t)
t.start()
yield(t, "timeout")

Comments

Don't forget to free the timer afterwards, or you'll cause a memory leak.

t.queue_free()

---

this works, but i tried to turn it into a function which didn't
anyone knows why?

func wait(s):
var t = Timer.new()
t.setwaittime(s)
t.setoneshot(true)
self.addchild(t)
t.start()
yield(t, "timeout")
t.queuefree()

func _ready():
hide()
wait(4)
show()

it took me legit 10 minute to create an account to ask this because u have to click on send me a confirmation mail. that's so unnecessary so here are some random chinese letters 阿贵冉宋日国

---

Weirdly enough, when I did this in it's own function, it didn't work, but when I had the exact same code on the place where I called the wait function, it worked.

---

This is not the best answer, since Godot has it's own dedicated function for this use-case: create_timer
(which is already mentioned in the comment below

So if you Googled this issue and ended up on this thread, check the create_timer function and yield-ing it instead of creating your own Timer

---

create_timer

is not a better idea. It can work in some cases, but if the object that creates the timer is freed, the game will crash. In general it's best to avoid using yields until Godot 4.0, as I believe they fixed the issue.

---

This causes any function you put this in to return a state instead of a value because of yield

---

If you are creating a wait(s) function and then calling it in another function, use yield in the calling method and wait for the "completed" signal of wait method.

yield(wait(2),"completed");

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Thank you! I know this was answered a long time ago but got me going!

Answer 2

See OS.delay_msec and OS.delay_usec.

Comments

Note that if you use those in the main thread, those will cause the project to freeze until the delay has expired.

Answer 3

yield(get_tree().create_timer(1.0), "timeout")

Comments

Does the timer created here get disposed?

---

I believe that, once the routine has been resumed, the SceneTreeTimer object, returned by the create_timer () function, becomes invalid, as documented at:
https://docs.godotengine.org/en/3.0/getting_started/scripting/gdscript/gdscript_basics.html?highlight=yield#coroutines-with-yield

---

this is causing my function to return

Answer 4

Use:
yield(get_tree().create_timer(1), "timeout").

That should yield the script for the specified amount of seconds (in this case, 1.)

Answer 5

In Godot 4:

GDScript:

func some_function():
    print("start")
    await get_tree().create_timer(1.0).timeout
    print("end")

C#:

public async void SomeFunction()
{
    GD.Print("start");
    await ToSignal(GetTree().CreateTimer(1.0f), "timeout");
    GD.Print("end");
}

Comments

thanks you so much ! this help me a lot in my current project