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0 votes
var q = ["Test1","Test2"]

Output: Test1

in Engine by (18 points)

1 Answer

+2 votes

q[0].erase(0,3) gets the value of q[0], not the reference to it, so doing anything with this value will not affect the value stored in the array itself.

This should work:

temp_string = q[0]
q[0] = temp_string

(Replaces the array element with the changed string)

Or even simpler:

q[0] = q[0].substr(4)

(Does everything in one step, but needs a method with a return value)

by (1,732 points)
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