How do I make queue_free() become false

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0 votes

I want queue_free() to return to the previous value, that is to say that the node is no longer eliminated and is visible again. when I stable the varlor
queue_free() the node is removed but I don't know how to redo it and return to the original state

in Engine by (196 points)

What is it that you are trying to do ? Maybe we can come up with another solution. As far as I know, I don't think queue free can be undone

by (418 points)

This might help > https://godotengine.org/qa/49429/what-is-difference-queue_free-and-remove_child-what-queue?show=49429#q49429

Also return means the datatype (and value) that the method retrieves. queue_free returns void because it executes an action rather than give you a value to work with like get_nodes_in_group which returns an array.

by (3,229 points)

5 Answers

0 votes

Remove your node from a parent if you want to reuse it latter, do not queue_free() it.

by (206 points)
0 votes

so how do i do it? to remove a node and then be back

by (196 points)

stop posting comments as answers, please

by (206 points)
0 votes

Use remove_child() and add_child() functions.

by (36 points)
0 votes

and then return to the previous state that is to say redo the deletion?

by (196 points)

stop posting comments as answers, please

by (206 points)
0 votes

If you only want to display or undisplay a node, use the property visible of the node.

get_node().set_visible()

or

get.node().visible =
by (36 points)
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